What is the answer to x^2 1/(\sqrt[3]{x)}=9x ?

The answer to x^2 1/(\sqrt[3]{x)}=9x is x=-27,x=27

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x^2 1/(\sqrt[3]{x)}=9x

x = - 27, x = 27

Solution steps

Expand

Take both sides of the equation to the power of

3 : x^{5} = 729 x^{3}

x^{5} = 729 x^{3}

Solve

x^{5} = 729 x^{3} : x = 0, x = - 27, x = 27

x = 0, x = - 27, x = 27

Verify Solutions:

x = 0

False

, x = - 27

True

, x = 27

True

The solutions are

x = - 27, x = 27

4 x + 8 + 13 = 19

b = 1.69 s + 4.45 - 3.49

100 - x - x = 10

4 x + 1 - x - 1 = 2

What is the answer to x^2 1/(\sqrt[3]{x)}=9x ?
The answer to x^2 1/(\sqrt[3]{x)}=9x is x=-27,x=27
Solve for x: x^2 1/(\sqrt[3]{x)}=9x
The solution is x=-27,x=27