What is the answer to 50=sqrt(20^2+x^2) ?

The answer to 50=sqrt(20^2+x^2) is x=10sqrt(21),x=-10sqrt(21)

Solve for x: 50=sqrt(20^2+x^2)

The solution is x=10sqrt(21),x=-10sqrt(21)

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50 = 2 0^{2} + x^{2}

x = 1021, x = - 1021

Decimal Notation

x = 45.82575 \dots, x = - 45.82575 \dots

Solution steps

50 = 2 0^{2} + x^{2}

Square both sides:

2500 = 400 + x^{2}

2500 = 400 + x^{2}

Solve

2500 = 400 + x^{2} : x = 1021, x = - 1021

x = 1021, x = - 1021

Verify Solutions:

x = 1021

True

, x = - 1021

True

The solutions are

x = 1021, x = - 1021

2 x = 4 x

(2 x - 2)^{\frac{1}{3}} = 4

x = 8 - 2 x

x^{\frac{4}{3}} - 81 = 0

6 - x = x

What is the answer to 50=sqrt(20^2+x^2) ?
The answer to 50=sqrt(20^2+x^2) is x=10sqrt(21),x=-10sqrt(21)
Solve for x: 50=sqrt(20^2+x^2)
The solution is x=10sqrt(21),x=-10sqrt(21)