What are the solutions to the equation 3x^2-x=2 ?

The solutions to the equation 3x^2-x=2 are x=1,x=-2/3

Find the zeros of 3x^2-x=2

The zeros of 3x^2-x=2 are x=1,x=-2/3

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3 x^{2} - x = 2

x = 1, x = - \frac{2}{3}

Decimal Notation

x = 1, x = - 0.66666 \dots

Solution steps

3 x^{2} - x = 2

Move

2

to the left side

3 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 2) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 3}

x = \frac{- ( - 1 ) + 5}{2 \cdot 3} : 1

x = \frac{- ( - 1 ) - 5}{2 \cdot 3} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{2}{3}

∣ x - 3 ∣ > 5

x^{3} - 3 x^{2} + 9 x - 27

2 n^{2} - 5 n - 3 = 0

x^{2} + x - \frac{15}{4} = 0

\frac{1 - 4 x}{3} = 3

What are the solutions to the equation 3x^2-x=2 ?
The solutions to the equation 3x^2-x=2 are x=1,x=-2/3
Find the zeros of 3x^2-x=2
The zeros of 3x^2-x=2 are x=1,x=-2/3