What is the answer to sqrt(26(4+k^2))=12-4k ?

The answer to sqrt(26(4+k^2))=12-4k is k=-10,k= 2/5

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sqrt(26(4+k^2))=12-4k

26 (4 + k^{2}) = 12 - 4 k

k = - 10, k = \frac{2}{5}

Decimal Notation

k = - 10, k = 0.4

Solution steps

26 (4 + k^{2}) = 12 - 4 k

Square both sides:

104 + 26 k^{2} = 144 - 96 k + 16 k^{2}

104 + 26 k^{2} = 144 - 96 k + 16 k^{2}

Solve

104 + 26 k^{2} = 144 - 96 k + 16 k^{2} : k = - 10, k = \frac{2}{5}

k = - 10, k = \frac{2}{5}

Verify Solutions:

k = - 10

True

, k = \frac{2}{5}

True

The solutions are

k = - 10, k = \frac{2}{5}

5 x + 4 = x - 4

u - 3 u + 2 = 0

2 x + 5 - 3 = x

x^{\frac{1}{2}} = \frac{1}{2}

y + y + 5 = 5

What is the answer to sqrt(26(4+k^2))=12-4k ?
The answer to sqrt(26(4+k^2))=12-4k is k=-10,k= 2/5
Solve for k: sqrt(26(4+k^2))=12-4k
The solution is k=-10,k= 2/5