What is the answer to solvefor x,y=sqrt(4-x^2) ?

The answer to solvefor x,y=sqrt(4-x^2) is x=sqrt(-y^2+4) {0<= y<= 2},x=-sqrt(-y^2+4) {0<= y<= 2}

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solvefor x,y=sqrt(4-x^2)

solve for

x, y = 4 - x^{2}

x = - y^{2} + 4 {0 \leq y \leq 2}, x = - - y^{2} + 4 {0 \leq y \leq 2}

Solution steps

y = 4 - x^{2}

Square both sides:

y^{2} = 4 - x^{2}

y^{2} = 4 - x^{2}

Solve

y^{2} = 4 - x^{2} : x = - y^{2} + 4, x = - - y^{2} + 4

x = - y^{2} + 4, x = - - y^{2} + 4

Verify Solutions:

x = - y^{2} + 4 {0 \leq y \leq 2}, x = - - y^{2} + 4 {0 \leq y \leq 2}

The solutions are

x = - y^{2} + 4 {0 \leq y \leq 2}, x = - - y^{2} + 4 {0 \leq y \leq 2}

3 x - 3 - x - 3 = - 2

x, g^{1} (x) = 6 - 4 x

x + 7 = 1

121 - x - x = 11

What is the answer to solvefor x,y=sqrt(4-x^2) ?
The answer to solvefor x,y=sqrt(4-x^2) is x=sqrt(-y^2+4) {0<= y<= 2},x=-sqrt(-y^2+4) {0<= y<= 2}