What is the answer to sqrt((x-7)^2+(-1-3)^2)=5 ?

The answer to sqrt((x-7)^2+(-1-3)^2)=5 is x=10,x=4

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sqrt((x-7)^2+(-1-3)^2)=5

(x - 7)^{2} + (- 1 - 3)^{2} = 5

x = 10, x = 4

Solution steps

(x - 7)^{2} + (- 1 - 3)^{2} = 5

Square both sides:

x^{2} - 14 x + 65 = 25

x^{2} - 14 x + 65 = 25

Solve

x^{2} - 14 x + 65 = 25 : x = 10, x = 4

x = 10, x = 4

Verify Solutions:

x = 10

True

, x = 4

True

The solutions are

x = 10, x = 4

x^{2} + 1 - \frac{1}{2} = x

x + 1 - 4 x - 3 = 1

7 x^{\frac{5}{4}} - 14 = 0

\frac{1}{1 - x ^{2}} = 2

2 k + 24 = - 8 - 2 k

What is the answer to sqrt((x-7)^2+(-1-3)^2)=5 ?
The answer to sqrt((x-7)^2+(-1-3)^2)=5 is x=10,x=4
Solve for x: sqrt((x-7)^2+(-1-3)^2)=5
The solution is x=10,x=4