What is the answer to solvefor y,x=sqrt(36-y^2) ?

The answer to solvefor y,x=sqrt(36-y^2) is y=sqrt(-x^2+36) {0<= x<= 6},y=-sqrt(-x^2+36) {0<= x<= 6}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,x=sqrt(36-y^2)

solve for

y, x = 36 - y^{2}

y = - x^{2} + 36 {0 \leq x \leq 6}, y = - - x^{2} + 36 {0 \leq x \leq 6}

Solution steps

x = 36 - y^{2}

Square both sides:

x^{2} = 36 - y^{2}

x^{2} = 36 - y^{2}

Solve

x^{2} = 36 - y^{2} : y = - x^{2} + 36, y = - - x^{2} + 36

y = - x^{2} + 36, y = - - x^{2} + 36

Verify Solutions:

y = - x^{2} + 36 {0 \leq x \leq 6}, y = - - x^{2} + 36 {0 \leq x \leq 6}

The solutions are

y = - x^{2} + 36 {0 \leq x \leq 6}, y = - - x^{2} + 36 {0 \leq x \leq 6}

r, c = 3 r

(x + 3)^{(\frac{2}{3})} = 8

y, x = y + 8

6 x = 3 x

x - 5 = x + 2

What is the answer to solvefor y,x=sqrt(36-y^2) ?
The answer to solvefor y,x=sqrt(36-y^2) is y=sqrt(-x^2+36) {0<= x<= 6},y=-sqrt(-x^2+36) {0<= x<= 6}