What is the answer to sqrt(x^2-3x+2)=sqrt(x-1) ?

The answer to sqrt(x^2-3x+2)=sqrt(x-1) is x=3,x=1

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sqrt(x^2-3x+2)=sqrt(x-1)

x^{2} - 3 x + 2 = x - 1

x = 3, x = 1

Solution steps

x^{2} - 3 x + 2 = x - 1

Square both sides:

x^{2} - 3 x + 2 = x - 1

x^{2} - 3 x + 2 = x - 1

Solve

x^{2} - 3 x + 2 = x - 1 : x = 3, x = 1

x = 3, x = 1

Verify Solutions:

x = 3

True

, x = 1

True

The solutions are

x = 3, x = 1

3 x^{\frac{5}{2}} - 28 = 68

x + 3 = x + 11

x - 7 - 2 x = - 1

2 y + 33 + 9 = y + 8

What is the answer to sqrt(x^2-3x+2)=sqrt(x-1) ?
The answer to sqrt(x^2-3x+2)=sqrt(x-1) is x=3,x=1
Solve for x: sqrt(x^2-3x+2)=sqrt(x-1)
The solution is x=3,x=1