What is the answer to sqrt(x+3)=\sqrt[4]{x^3-9x} ?

The answer to sqrt(x+3)=\sqrt[4]{x^3-9x} is x=-3,x=2+sqrt(7),x=2-sqrt(7)

Solve for x: sqrt(x+3)=\sqrt[4]{x^3-9x}

The solution is x=-3,x=2+sqrt(7),x=2-sqrt(7)

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x = - 3, x = 2 + 7, x = 2 - 7

Decimal Notation

x = - 3, x = 4.64575 \dots, x = - 0.64575 \dots

Solution steps

Take both sides of the equation to the power of

4 : (x + 3)^{2} = x^{3} - 9 x

(x + 3)^{2} = x^{3} - 9 x

Solve

(x + 3)^{2} = x^{3} - 9 x : x = - 3, x = 2 + 7, x = 2 - 7

x = - 3, x = 2 + 7, x = 2 - 7

Verify Solutions:

x = - 3

True

, x = 2 + 7

True

, x = 2 - 7

True

The solutions are

x = - 3, x = 2 + 7, x = 2 - 7

2 x + 1 - 2 = 6

25 - z - z = 5

9 x^{2} - 11 x + 6 x 5 - 2 x = 23

13 - 4 x = x + 8

\frac{3}{4} x - 4 = 6

What is the answer to sqrt(x+3)=\sqrt[4]{x^3-9x} ?
The answer to sqrt(x+3)=\sqrt[4]{x^3-9x} is x=-3,x=2+sqrt(7),x=2-sqrt(7)
Solve for x: sqrt(x+3)=\sqrt[4]{x^3-9x}
The solution is x=-3,x=2+sqrt(7),x=2-sqrt(7)