What is the answer to 2x-sqrt(5-2x)=0 ?

The answer to 2x-sqrt(5-2x)=0 is x=(-1+sqrt(21))/4

Solve for x: 2x-sqrt(5-2x)=0

The solution is x=(-1+sqrt(21))/4

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2 x - 5 - 2 x = 0

x = \frac{- 1 + 21}{4}

Decimal Notation

x = 0.89564 \dots

Solution steps

2 x - 5 - 2 x = 0

Remove square roots

5 - 2 x = 4 x^{2}

Solve

5 - 2 x = 4 x^{2} : x = \frac{- 1 + 21}{4}, x = - \frac{1 + 21}{4}

x = \frac{- 1 + 21}{4}, x = - \frac{1 + 21}{4}

Verify Solutions:

x = \frac{- 1 + 21}{4}

True

, x = - \frac{1 + 21}{4}

False

The solution is

x = \frac{- 1 + 21}{4}

2 (x + 15) - 3 = x

3 x^{\frac{3}{4}} = 24

x^{2} + x = 0

3 t + 9 = - 6

t + 2 = 3 t - 1

What is the answer to 2x-sqrt(5-2x)=0 ?
The answer to 2x-sqrt(5-2x)=0 is x=(-1+sqrt(21))/4
Solve for x: 2x-sqrt(5-2x)=0
The solution is x=(-1+sqrt(21))/4