What is the answer to 2\sqrt[3]{3x+2}=\sqrt[3]{4x-9} ?

The answer to 2\sqrt[3]{3x+2}=\sqrt[3]{4x-9} is x=-5/4

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2\sqrt[3]{3x+2}=\sqrt[3]{4x-9}

x = - \frac{5}{4}

Decimal Notation

x = - 1.25

Solution steps

Take both sides of the equation to the power of

3 : 24 x + 16 = 4 x - 9

24 x + 16 = 4 x - 9

Solve

24 x + 16 = 4 x - 9 : x = - \frac{5}{4}

x = - \frac{5}{4}

Verify Solutions:

x = - \frac{5}{4}

True

The solution is

x = - \frac{5}{4}

7 t + 5 = 8

4 x^{2} - 12 x + 9 = 3 - 2 x

x + 7 = 6 + 4 x

2 x = 4 x^{2} - 5 x + 50

3 (x + 2)^{\frac{3}{2}} = 24

What is the answer to 2\sqrt[3]{3x+2}=\sqrt[3]{4x-9} ?
The answer to 2\sqrt[3]{3x+2}=\sqrt[3]{4x-9} is x=-5/4
Solve for x: 2\sqrt[3]{3x+2}=\sqrt[3]{4x-9}
The solution is x=-5/4