What are the solutions to the equation y^2+8y-9=0 ?

The solutions to the equation y^2+8y-9=0 are y=1,y=-9

Find the zeros of y^2+8y-9=0

The zeros of y^2+8y-9=0 are y=1,y=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + 8 y - 9 = 0

y = 1, y = - 9

Solution steps

y^{2} + 8 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 9) = 10

y_{1, 2} = \frac{- 8 \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 10}{2 \cdot 1}, y_{2} = \frac{- 8 - 10}{2 \cdot 1}

y = \frac{- 8 + 10}{2 \cdot 1} : 1

y = \frac{- 8 - 10}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

y = 1, y = - 9

1^{2} + 2^{2} = c^{2}

x - 4 \leq 3 x + 10 < 10 - 4 x

- 3 x - 3 = (x - 2) (x + 1)

x^{2} - 4 x - 14 = - 2

\frac{5 x - 1}{3} > 5

What are the solutions to the equation y^2+8y-9=0 ?
The solutions to the equation y^2+8y-9=0 are y=1,y=-9
Find the zeros of y^2+8y-9=0
The zeros of y^2+8y-9=0 are y=1,y=-9