What is the answer to sqrt(4a^2-4a+1+(a+4))=a+7 ?

The answer to sqrt(4a^2-4a+1+(a+4))=a+7 is a=(17+sqrt(817))/6 ,a=(17-sqrt(817))/6

Solve for a: sqrt(4a^2-4a+1+(a+4))=a+7

The solution is a=(17+sqrt(817))/6 ,a=(17-sqrt(817))/6

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4 a^{2} - 4 a + 1 + (a + 4) = a + 7

a = \frac{17 + 817}{6}, a = \frac{17 - 817}{6}

Decimal Notation

a = 7.59720 \dots, a = - 1.93053 \dots

Solution steps

4 a^{2} - 4 a + 1 + (a + 4) = a + 7

Square both sides:

4 a^{2} - 3 a + 5 = a^{2} + 14 a + 49

4 a^{2} - 3 a + 5 = a^{2} + 14 a + 49

Solve

4 a^{2} - 3 a + 5 = a^{2} + 14 a + 49 : a = \frac{17 + 817}{6}, a = \frac{17 - 817}{6}

a = \frac{17 + 817}{6}, a = \frac{17 - 817}{6}

Verify Solutions:

a = \frac{17 + 817}{6}

True

, a = \frac{17 - 817}{6}

True

The solutions are

a = \frac{17 + 817}{6}, a = \frac{17 - 817}{6}

(x^{2} + 15)^{\frac{1}{2}} = 8

2 x = 10 + 3 x

x^{(\frac{3}{2})} = 8

11 + 1 - 3 x = 15

2 n + 28 - 4 n = 0

What is the answer to sqrt(4a^2-4a+1+(a+4))=a+7 ?
The answer to sqrt(4a^2-4a+1+(a+4))=a+7 is a=(17+sqrt(817))/6 ,a=(17-sqrt(817))/6
Solve for a: sqrt(4a^2-4a+1+(a+4))=a+7
The solution is a=(17+sqrt(817))/6 ,a=(17-sqrt(817))/6