What is the answer to \sqrt[3]{2+x}+\sqrt[3]{2-x}=1 ?

The answer to \sqrt[3]{2+x}+\sqrt[3]{2-x}=1 is x=sqrt(5),x=-sqrt(5)

Solve for x: \sqrt[3]{2+x}+\sqrt[3]{2-x}=1

The solution is x=sqrt(5),x=-sqrt(5)

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Popular >

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

Rewrite the equation with

and

x = u^{3} - 2

Solve

u = \frac{1 + 5}{2}, u = \frac{1 - 5}{2}

Substitute back

solve for

x

Solve

x = 5, x = - 5

Verify Solutions:

x = 5

True

, x = - 5

True

The solutions are

x = 5, x = - 5

x + 2 + 2 x - 1 = 5

x^{\frac{3}{2}} = 3

x^{\frac{3}{2}} = 0

x^{(\frac{3}{2})} = 27

(x - 1)^{\frac{2}{3}} = 64

What is the answer to \sqrt[3]{2+x}+\sqrt[3]{2-x}=1 ?
The answer to \sqrt[3]{2+x}+\sqrt[3]{2-x}=1 is x=sqrt(5),x=-sqrt(5)
Solve for x: \sqrt[3]{2+x}+\sqrt[3]{2-x}=1
The solution is x=sqrt(5),x=-sqrt(5)