What is the answer to 5=sqrt((3-x)^2+(9-5)^2) ?

The answer to 5=sqrt((3-x)^2+(9-5)^2) is x=6,x=0

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5=sqrt((3-x)^2+(9-5)^2)

5 = (3 - x)^{2} + (9 - 5)^{2}

x = 6, x = 0

Solution steps

5 = (3 - x)^{2} + (9 - 5)^{2}

Square both sides:

25 = x^{2} - 6 x + 25

25 = x^{2} - 6 x + 25

Solve

25 = x^{2} - 6 x + 25 : x = 6, x = 0

x = 6, x = 0

Verify Solutions:

x = 6

True

, x = 0

True

The solutions are

x = 6, x = 0

x + 6 - x - 1 = 1

5 - 2 x = - x + 1

x + 3 x - 2 = 4

8 x - 1 = 7

w = 9 w - 20

What is the answer to 5=sqrt((3-x)^2+(9-5)^2) ?
The answer to 5=sqrt((3-x)^2+(9-5)^2) is x=6,x=0
Solve for x: 5=sqrt((3-x)^2+(9-5)^2)
The solution is x=6,x=0