What is the answer to x^2=sqrt(1-x^2) ?

The answer to x^2=sqrt(1-x^2) is x=sqrt((-1+\sqrt{5))/2},x=-sqrt((-1+\sqrt{5))/2}

Solve for x: x^2=sqrt(1-x^2)

The solution is x=sqrt((-1+\sqrt{5))/2},x=-sqrt((-1+\sqrt{5))/2}

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Popular >

x^{2} = 1 - x^{2}

x = \frac{- 1 + 5}{2}, x = - \frac{- 1 + 5}{2}

Decimal Notation

x = 0.78615 \dots, x = - 0.78615 \dots

Solution steps

x^{2} = 1 - x^{2}

Square both sides:

x^{4} = 1 - x^{2}

x^{4} = 1 - x^{2}

Solve

x^{4} = 1 - x^{2} : x = \frac{- 1 + 5}{2}, x = - \frac{- 1 + 5}{2}

x = \frac{- 1 + 5}{2}, x = - \frac{- 1 + 5}{2}

Verify Solutions:

x = \frac{- 1 + 5}{2}

True

, x = - \frac{- 1 + 5}{2}

True

The solutions are

x = \frac{- 1 + 5}{2}, x = - \frac{- 1 + 5}{2}

u = 10

3 = 4 x - 3

100000 = 0.1877 B^{0.9747}

9 x + 67 = x + 5

u - 6 = 6

What is the answer to x^2=sqrt(1-x^2) ?
The answer to x^2=sqrt(1-x^2) is x=sqrt((-1+\sqrt{5))/2},x=-sqrt((-1+\sqrt{5))/2}
Solve for x: x^2=sqrt(1-x^2)
The solution is x=sqrt((-1+\sqrt{5))/2},x=-sqrt((-1+\sqrt{5))/2}