What is the answer to 1+\sqrt[3]{2x-1}=-2 ?

The answer to 1+\sqrt[3]{2x-1}=-2 is x=-13

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1+\sqrt[3]{2x-1}=-2

x = - 13

Solution steps

Move

1

to the right side

Take both sides of the equation to the power of

3 : 2 x - 1 = - 27

2 x - 1 = - 27

Solve

2 x - 1 = - 27 : x = - 13

x = - 13

Verify Solutions:

x = - 13

True

The solution is

x = - 13

x^{0.36} = 4.63

y, x = y 1 - y^{2}

(x^{2} + 3 x + 7)^{\frac{1}{2}} = 5

1 - \frac{1}{x} = 0

2 x + 4 = 0

What is the answer to 1+\sqrt[3]{2x-1}=-2 ?
The answer to 1+\sqrt[3]{2x-1}=-2 is x=-13
Solve for x: 1+\sqrt[3]{2x-1}=-2
The solution is x=-13