What is the answer to sqrt((2x)^2+(2x+1)^2)=566 ?

The answer to sqrt((2x)^2+(2x+1)^2)=566 is x=(-1+sqrt(640711))/4 ,x=-(1+sqrt(640711))/4

Solve for x: sqrt((2x)^2+(2x+1)^2)=566

The solution is x=(-1+sqrt(640711))/4 ,x=-(1+sqrt(640711))/4

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(2 x)^{2} + (2 x + 1)^{2} = 566

x = \frac{- 1 + 640711}{4}, x = - \frac{1 + 640711}{4}

Decimal Notation

x = 199.86106 \dots, x = - 200.36106 \dots

Solution steps

(2 x)^{2} + (2 x + 1)^{2} = 566

Square both sides:

8 x^{2} + 4 x + 1 = 320356

8 x^{2} + 4 x + 1 = 320356

Solve

8 x^{2} + 4 x + 1 = 320356 : x = \frac{- 1 + 640711}{4}, x = - \frac{1 + 640711}{4}

x = \frac{- 1 + 640711}{4}, x = - \frac{1 + 640711}{4}

Verify Solutions:

x = \frac{- 1 + 640711}{4}

True

, x = - \frac{1 + 640711}{4}

True

The solutions are

x = \frac{- 1 + 640711}{4}, x = - \frac{1 + 640711}{4}

\frac{2}{x} = 0.4

4 x - x^{2} = 0

x^{2} + 9 + 1 = x + 3

(6 x + 4)^{\frac{1}{2}} = 2

4 p x = \frac{x ^{2}}{4 p}

What is the answer to sqrt((2x)^2+(2x+1)^2)=566 ?
The answer to sqrt((2x)^2+(2x+1)^2)=566 is x=(-1+sqrt(640711))/4 ,x=-(1+sqrt(640711))/4
Solve for x: sqrt((2x)^2+(2x+1)^2)=566
The solution is x=(-1+sqrt(640711))/4 ,x=-(1+sqrt(640711))/4