What is the answer to \sqrt[3]{x^2-4}=0 ?

The answer to \sqrt[3]{x^2-4}=0 is x=2,x=-2

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\sqrt[3]{x^2-4}=0

x = 2, x = - 2

Solution steps

Take both sides of the equation to the power of

3 : x^{2} - 4 = 0

x^{2} - 4 = 0

Solve

x^{2} - 4 = 0 : x = 2, x = - 2

x = 2, x = - 2

Verify Solutions:

x = 2

True

, x = - 2

True

The solutions are

x = 2, x = - 2

x + 3 + x - 2 = 5

a = x^{2} - 1

- 1 = (- 2)^{2} + (- 2) + c_{1}

x - 1 = 3 x - 13

1 + x x^{2} + 24 = x + 1

What is the answer to \sqrt[3]{x^2-4}=0 ?
The answer to \sqrt[3]{x^2-4}=0 is x=2,x=-2
Solve for x: \sqrt[3]{x^2-4}=0
The solution is x=2,x=-2