What is the answer to (x-1)^2-sqrt(x+1)=0 ?

The answer to (x-1)^2-sqrt(x+1)=0 is x=0,x\approx 2.35320…

Solve for x: (x-1)^2-sqrt(x+1)=0

The solution is x=0,x\approx 2.35320…

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(x - 1)^{2} - x + 1 = 0

x = 0, x \approx 2.35320 \dots

Solution steps

(x - 1)^{2} - x + 1 = 0

Expand

(x - 1)^{2} - x + 1 : x^{2} - 2 x + 1 - x + 1

x^{2} - 2 x + 1 - x + 1 = 0

Remove square roots

x + 1 = x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1

Solve

x + 1 = x^{4} - 4 x^{3} + 6 x^{2} - 4 x + 1 : x = 0, x \approx 2.35320 \dots

x = 0, x \approx 2.35320 \dots

Verify Solutions:

x = 0

True

, x \approx 2.35320 \dots

True

The solutions are

x = 0, x \approx 2.35320 \dots

x^{2} = 5 + x

c = 8 W

5 x + 1 = 2 x + 1 + 2

x + 10 - 1 = x

8 - x + 6 = 3

What is the answer to (x-1)^2-sqrt(x+1)=0 ?
The answer to (x-1)^2-sqrt(x+1)=0 is x=0,x\approx 2.35320…
Solve for x: (x-1)^2-sqrt(x+1)=0
The solution is x=0,x\approx 2.35320…