What is the answer to 0=(xsqrt(4-x^2))^2 ?

The answer to 0=(xsqrt(4-x^2))^2 is x=2,x=-2,x=0

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0=(xsqrt(4-x^2))^2

0 = (x 4 - x^{2})^{2}

x = 2, x = - 2, x = 0

Solution steps

0 = (x 4 - x^{2})^{2}

Switch sides

(x 4 - x^{2})^{2} = 0

Factor

(x 4 - x^{2})^{2} : (4 - x^{2}) x^{2}

(4 - x^{2}) x^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 - x^{2} = 0 or x = 0

Solve

4 - x^{2} = 0 : x = 2, x = - 2

x = 2, x = - 2, x = 0

Verify Solutions:

x = 2

True

, x = - 2

True

, x = 0

True

The solutions are

x = 2, x = - 2, x = 0

2 m + 4 - 10 = 8

x^{\frac{2}{3}} = - 16

\frac{2 ^{2}}{2} + c_{1} = 2

x, x - 3 + 5 = x

What is the answer to 0=(xsqrt(4-x^2))^2 ?
The answer to 0=(xsqrt(4-x^2))^2 is x=2,x=-2,x=0
Solve for x: 0=(xsqrt(4-x^2))^2
The solution is x=2,x=-2,x=0