What is the answer to 16=sqrt((12+4)^2+(x-2)^2) ?

The answer to 16=sqrt((12+4)^2+(x-2)^2) is x=2

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16=sqrt((12+4)^2+(x-2)^2)

16 = (12 + 4)^{2} + (x - 2)^{2}

x = 2

Solution steps

16 = (12 + 4)^{2} + (x - 2)^{2}

Square both sides:

256 = x^{2} - 4 x + 260

256 = x^{2} - 4 x + 260

Solve

256 = x^{2} - 4 x + 260 : x = 2

x = 2

Verify Solutions:

x = 2

True

The solution is

x = 2

x - 14 x + 45 = 0

(6 x^{2} + 30 x)^{\frac{3}{2}} = 216

161 + 46 x - x = 15

y, x = 3 y - 15

x + 4 x - 23 = 7

What is the answer to 16=sqrt((12+4)^2+(x-2)^2) ?
The answer to 16=sqrt((12+4)^2+(x-2)^2) is x=2
Solve for x: 16=sqrt((12+4)^2+(x-2)^2)
The solution is x=2