What is the answer to sqrt(3x-2)=-1+2x^2 ?

The answer to sqrt(3x-2)=-1+2x^2 is x=1

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sqrt(3x-2)=-1+2x^2

3 x - 2 = - 1 + 2 x^{2}

x = 1

Solution steps

3 x - 2 = - 1 + 2 x^{2}

Square both sides:

3 x - 2 = 1 - 4 x^{2} + 4 x^{4}

3 x - 2 = 1 - 4 x^{2} + 4 x^{4}

Solve

3 x - 2 = 1 - 4 x^{2} + 4 x^{4} : x = 1, x \approx 0.67012 \dots

x = 1, x \approx 0.67012 \dots

Verify Solutions:

x = 1

True

, x \approx 0.67012 \dots

False

The solution is

x = 1

x + 1 = 1

x, f (x - 3) = x + 3 + 4

x + x - 12 = 6

3 x + 25 = x - 5

4 x + 28 = x + 4

What is the answer to sqrt(3x-2)=-1+2x^2 ?
The answer to sqrt(3x-2)=-1+2x^2 is x=1
Solve for x: sqrt(3x-2)=-1+2x^2
The solution is x=1