What is the answer to sqrt(x^2)=sqrt(2(x+1)^2) ?

The answer to sqrt(x^2)=sqrt(2(x+1)^2) is x=-2+sqrt(2),x=-2-sqrt(2)

Solve for x: sqrt(x^2)=sqrt(2(x+1)^2)

The solution is x=-2+sqrt(2),x=-2-sqrt(2)

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x^{2} = 2 (x + 1)^{2}

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

x^{2} = 2 (x + 1)^{2}

Square both sides:

x^{2} = 2 x^{2} + 4 x + 2

x^{2} = 2 x^{2} + 4 x + 2

Solve

x^{2} = 2 x^{2} + 4 x + 2 : x = - 2 + 2, x = - 2 - 2

x = - 2 + 2, x = - 2 - 2

Verify Solutions:

x = - 2 + 2

True

, x = - 2 - 2

True

The solutions are

x = - 2 + 2, x = - 2 - 2

x + 5 - 3 x + 3 = 0

x - 1 = x + 1

t - 2 \frac{1}{t} = 1

v = 2 π G m r^{3}, r

What is the answer to sqrt(x^2)=sqrt(2(x+1)^2) ?
The answer to sqrt(x^2)=sqrt(2(x+1)^2) is x=-2+sqrt(2),x=-2-sqrt(2)
Solve for x: sqrt(x^2)=sqrt(2(x+1)^2)
The solution is x=-2+sqrt(2),x=-2-sqrt(2)