What is the answer to 13=sqrt((7-X)^2+(16-4)^2) ?

The answer to 13=sqrt((7-X)^2+(16-4)^2) is X=12,X=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

13=sqrt((7-X)^2+(16-4)^2)

13 = (7 - X)^{2} + (16 - 4)^{2}

X = 12, X = 2

Solution steps

13 = (7 - X)^{2} + (16 - 4)^{2}

Square both sides:

169 = X^{2} - 14 X + 193

169 = X^{2} - 14 X + 193

Solve

169 = X^{2} - 14 X + 193 : X = 12, X = 2

X = 12, X = 2

Verify Solutions:

X = 12

True

, X = 2

True

The solutions are

X = 12, X = 2

x + 2 = 32

(x + 1) - 27 x + 1 + 170 = 0

x + 1 = 8 - 2 x

b - 6 = 3 b - 20

x + 148 = x + 16

What is the answer to 13=sqrt((7-X)^2+(16-4)^2) ?
The answer to 13=sqrt((7-X)^2+(16-4)^2) is X=12,X=2
Solve for X: 13=sqrt((7-X)^2+(16-4)^2)
The solution is X=12,X=2