What is the answer to sqrt((x+2)^2+12)=4 ?

The answer to sqrt((x+2)^2+12)=4 is x=0,x=-4

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sqrt((x+2)^2+12)=4

(x + 2)^{2} + 12 = 4

x = 0, x = - 4

Solution steps

(x + 2)^{2} + 12 = 4

Square both sides:

x^{2} + 4 x + 16 = 16

x^{2} + 4 x + 16 = 16

Solve

x^{2} + 4 x + 16 = 16 : x = 0, x = - 4

x = 0, x = - 4

Verify Solutions:

x = 0

True

, x = - 4

True

The solutions are

x = 0, x = - 4

2 x = 18

2 x = 12

x - 6 - 8 = - x

2 x = 20

5 x + 10 = 7 x - 12

What is the answer to sqrt((x+2)^2+12)=4 ?
The answer to sqrt((x+2)^2+12)=4 is x=0,x=-4
Solve for x: sqrt((x+2)^2+12)=4
The solution is x=0,x=-4