What is the answer to solvefor x,y=sqrt(4-4x) ?

The answer to solvefor x,y=sqrt(4-4x) is x=-(y^2-4)/4 {y>= 0}

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solvefor x,y=sqrt(4-4x)

solve for

x, y = 4 - 4 x

x = - \frac{y ^{2} - 4}{4} {y \geq 0}

Solution steps

y = 4 - 4 x

Square both sides:

y^{2} = 4 - 4 x

y^{2} = 4 - 4 x

Solve

y^{2} = 4 - 4 x : x = - \frac{y ^{2} - 4}{4}

x = - \frac{y ^{2} - 4}{4}

Verify Solutions:

x = - \frac{y ^{2} - 4}{4} {y \geq 0}

The solution is

x = - \frac{y ^{2} - 4}{4} {y \geq 0}

y 1 - (1 - y^{2})^{2} = 0

- 3 - 2 x = 9

x, y - 1 = 4 - x^{2}

6 + 8 y = 6 + 8

5 x^{2} = 15

What is the answer to solvefor x,y=sqrt(4-4x) ?
The answer to solvefor x,y=sqrt(4-4x) is x=-(y^2-4)/4 {y>= 0}