What is the answer to solvefor a,-f=sqrt(2-a)+5 ?

The answer to solvefor a,-f=sqrt(2-a)+5 is a=-f^2-10f-23 {f<=-5}

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solvefor a,-f=sqrt(2-a)+5

solve for

a, - f = 2 - a + 5

a = - f^{2} - 10 f - 23 {f \leq - 5}

Solution steps

- f = 2 - a + 5

Switch sides

2 - a + 5 = - f

Move

5

to the right side

2 - a = - f - 5

Square both sides:

2 - a = f^{2} + 10 f + 25

2 - a = f^{2} + 10 f + 25

Solve

2 - a = f^{2} + 10 f + 25 : a = - f^{2} - 10 f - 23

a = - f^{2} - 10 f - 23

Verify Solutions:

a = - f^{2} - 10 f - 23 {f \leq - 5}

The solution is

a = - f^{2} - 10 f - 23 {f \leq - 5}

- 1 = - (- 2)^{2} + (- 2) + c_{1}

3 x^{2} = \frac{x}{3}

t - 4 t - 21 = 0

x - 14 - 5 x = 0

What is the answer to solvefor a,-f=sqrt(2-a)+5 ?
The answer to solvefor a,-f=sqrt(2-a)+5 is a=-f^2-10f-23 {f<=-5}