What is the answer to x^2-6x+9=sqrt(-x+3) ?

The answer to x^2-6x+9=sqrt(-x+3) is x=2,x=3

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x^2-6x+9=sqrt(-x+3)

x^{2} - 6 x + 9 = - x + 3

x = 2, x = 3

Solution steps

x^{2} - 6 x + 9 = - x + 3

Square both sides:

x^{4} - 12 x^{3} + 54 x^{2} - 108 x + 81 = - x + 3

x^{4} - 12 x^{3} + 54 x^{2} - 108 x + 81 = - x + 3

Solve

x^{4} - 12 x^{3} + 54 x^{2} - 108 x + 81 = - x + 3 : x = 2, x = 3

x = 2, x = 3

Verify Solutions:

x = 2

True

, x = 3

True

The solutions are

x = 2, x = 3

1 = x^{\frac{2}{3}}

x - 4 x + 4 = 0

2 x - 2 x - 3 = x + 2

2 x^{2} + x + 1 = 1

8 x^{\frac{3}{2}} - 40 = 0

What is the answer to x^2-6x+9=sqrt(-x+3) ?
The answer to x^2-6x+9=sqrt(-x+3) is x=2,x=3
Solve for x: x^2-6x+9=sqrt(-x+3)
The solution is x=2,x=3