What is the answer to sqrt(x^2-2x+1)=x^2-3 ?

The answer to sqrt(x^2-2x+1)=x^2-3 is x=2,x=(-1-sqrt(17))/2

Solve for x: sqrt(x^2-2x+1)=x^2-3

The solution is x=2,x=(-1-sqrt(17))/2

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x^{2} - 2 x + 1 = x^{2} - 3

x = 2, x = \frac{- 1 - 17}{2}

Decimal Notation

x = 2, x = - 2.56155 \dots

Solution steps

x^{2} - 2 x + 1 = x^{2} - 3

Square both sides:

x^{2} - 2 x + 1 = x^{4} - 6 x^{2} + 9

x^{2} - 2 x + 1 = x^{4} - 6 x^{2} + 9

Solve

x^{2} - 2 x + 1 = x^{4} - 6 x^{2} + 9 : x = - 1, x = 2, x = \frac{- 1 + 17}{2}, x = \frac{- 1 - 17}{2}

x = - 1, x = 2, x = \frac{- 1 + 17}{2}, x = \frac{- 1 - 17}{2}

Verify Solutions:

x = - 1

False

, x = 2

True

, x = \frac{- 1 + 17}{2}

False

, x = \frac{- 1 - 17}{2}

True

The solutions are

x = 2, x = \frac{- 1 - 17}{2}

8 = 3 x - 2

- 3 - 4 x - - 2 - 2 x = 1

x + 2 = 3 + 5 x

7 x + 28 = x + 4

What is the answer to sqrt(x^2-2x+1)=x^2-3 ?
The answer to sqrt(x^2-2x+1)=x^2-3 is x=2,x=(-1-sqrt(17))/2
Solve for x: sqrt(x^2-2x+1)=x^2-3
The solution is x=2,x=(-1-sqrt(17))/2