What is the answer to \sqrt[3]{20-x}+x-6=0 ?

The answer to \sqrt[3]{20-x}+x-6=0 is x\approx 3.45169…

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\sqrt[3]{20-x}+x-6=0

x \approx 3.45169 \dots

Solution steps

Remove roots

20 - x = - x^{3} + 18 x^{2} - 108 x + 216

Solve

20 - x = - x^{3} + 18 x^{2} - 108 x + 216 : x \approx 3.45169 \dots

x \approx 3.45169 \dots

Verify Solutions:

x \approx 3.45169 \dots

True

The solution is

x \approx 3.45169 \dots

10 z + 7 + \frac{z}{3} = 0

x - 5 + 7 = 11

x - 4 \cdot x + 3 = 0

8 x = 48 - x

What is the answer to \sqrt[3]{20-x}+x-6=0 ?
The answer to \sqrt[3]{20-x}+x-6=0 is x\approx 3.45169…
Solve for x: \sqrt[3]{20-x}+x-6=0
The solution is x\approx 3.45169…