What is the answer to 2sqrt((x-3))+x-6=0 ?

The answer to 2sqrt((x-3))+x-6=0 is x=4

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2sqrt((x-3))+x-6=0

2 (x - 3) + x - 6 = 0

x = 4

Solution steps

2 (x - 3) + x - 6 = 0

Remove square roots

4 x - 12 = x^{2} - 12 x + 36

Solve

4 x - 12 = x^{2} - 12 x + 36 : x = 12, x = 4

x = 12, x = 4

Verify Solutions:

x = 12

False

, x = 4

True

The solution is

x = 4

x^{\frac{1}{2}} = 7

y + y - 4 = 4

3 x + 1 = x + 1

x^{2} - 2 x + \frac{1}{2} = 0

x - 2 = 4

What is the answer to 2sqrt((x-3))+x-6=0 ?
The answer to 2sqrt((x-3))+x-6=0 is x=4
Solve for x: 2sqrt((x-3))+x-6=0
The solution is x=4