What is the answer to \sqrt[5]{x^2+18x}=-2 ?

The answer to \sqrt[5]{x^2+18x}=-2 is x=-2,x=-16

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\sqrt[5]{x^2+18x}=-2

x = - 2, x = - 16

Solution steps

Take both sides of the equation to the power of

5 : x^{2} + 18 x = - 32

x^{2} + 18 x = - 32

Solve

x^{2} + 18 x = - 32 : x = - 2, x = - 16

x = - 2, x = - 16

Verify Solutions:

x = - 2

True

, x = - 16

True

The solutions are

x = - 2, x = - 16

2 + x + 1 = x - 1

10 = 50 k

x, x + x^{2} = 0

x^{2} - 8 x = 3

What is the answer to \sqrt[5]{x^2+18x}=-2 ?
The answer to \sqrt[5]{x^2+18x}=-2 is x=-2,x=-16
Solve for x: \sqrt[5]{x^2+18x}=-2
The solution is x=-2,x=-16