What is the answer to 1=sqrt(x^2+x^2+x^2) ?

The answer to 1=sqrt(x^2+x^2+x^2) is x= 1/(sqrt(3)),x=-1/(sqrt(3))

Solve for x: 1=sqrt(x^2+x^2+x^2)

The solution is x= 1/(sqrt(3)),x=-1/(sqrt(3))

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1 = x^{2} + x^{2} + x^{2}

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

1 = x^{2} + x^{2} + x^{2}

Square both sides:

1 = 3 x^{2}

1 = 3 x^{2}

Solve

1 = 3 x^{2} : x = \frac{1}{3}, x = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

Verify Solutions:

x = \frac{1}{3}

True

, x = - \frac{1}{3}

True

The solutions are

x = \frac{1}{3}, x = - \frac{1}{3}

3 p^{2} + 6 + 3 = 6 p

(2 x + 3)^{\frac{1}{2}} - 2 = x

What is the answer to 1=sqrt(x^2+x^2+x^2) ?
The answer to 1=sqrt(x^2+x^2+x^2) is x= 1/(sqrt(3)),x=-1/(sqrt(3))
Solve for x: 1=sqrt(x^2+x^2+x^2)
The solution is x= 1/(sqrt(3)),x=-1/(sqrt(3))