What is the answer to sqrt(x^2+3x-1)-2x=-1 ?

The answer to sqrt(x^2+3x-1)-2x=-1 is x=2

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sqrt(x^2+3x-1)-2x=-1

x^{2} + 3 x - 1 - 2 x = - 1

x = 2

Solution steps

x^{2} + 3 x - 1 - 2 x = - 1

Remove square roots

x^{2} + 3 x - 1 = 1 - 4 x + 4 x^{2}

Solve

x^{2} + 3 x - 1 = 1 - 4 x + 4 x^{2} : x = \frac{1}{3}, x = 2

x = \frac{1}{3}, x = 2

Verify Solutions:

x = \frac{1}{3}

False

, x = 2

True

The solution is

x = 2

y - 2 = 24 - 3 y

3 - x = 3 x + 5

y, x = 2 - y

x + 6 = 4

What is the answer to sqrt(x^2+3x-1)-2x=-1 ?
The answer to sqrt(x^2+3x-1)-2x=-1 is x=2
Solve for x: sqrt(x^2+3x-1)-2x=-1
The solution is x=2