What is the answer to (x^2-1)(sqrt(2x-1))=0 ?

The answer to (x^2-1)(sqrt(2x-1))=0 is x= 1/2 ,x=1

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(x^2-1)(sqrt(2x-1))=0

(x^{2} - 1) (2 x - 1) = 0

x = \frac{1}{2}, x = 1

Decimal Notation

x = 0.5, x = 1

Solution steps

(x^{2} - 1) (2 x - 1) = 0

Factor

(x^{2} - 1) 2 x - 1 : 2 x - 1 (x + 1) (x - 1)

2 x - 1 (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 1 = 0 or x - 1 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

x = \frac{1}{2}, x = - 1, x = 1

Verify Solutions:

x = \frac{1}{2}

True

, x = - 1

False

, x = 1

True

The solutions are

x = \frac{1}{2}, x = 1

4 x - 7 = 9

4 x - 7 = 5

9.66 = 0.0017 \cdot X^{1.56}

x = 4 x + 1 + 5

What is the answer to (x^2-1)(sqrt(2x-1))=0 ?
The answer to (x^2-1)(sqrt(2x-1))=0 is x= 1/2 ,x=1
Solve for x: (x^2-1)(sqrt(2x-1))=0
The solution is x= 1/2 ,x=1