What is the answer to solvefor t,Y=2t^{1/2} ?

The answer to solvefor t,Y=2t^{1/2} is t=(Y^2)/4 {Y>= 0}

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solvefor t,Y=2t^{1/2}

solve for

t, Y = 2 t^{\frac{1}{2}}

t = \frac{Y ^{2}}{4} {Y \geq 0}

Solution steps

Y = 2 t^{\frac{1}{2}}

Switch sides

2 t^{\frac{1}{2}} = Y

Divide both sides by

2

t^{\frac{1}{2}} = \frac{Y}{2}

Square both sides:

t = \frac{Y ^{2}}{4}

t = \frac{Y ^{2}}{4}

Verify Solutions:

t = \frac{Y ^{2}}{4} {Y \geq 0}

The solution is

t = \frac{Y ^{2}}{4} {Y \geq 0}

x = 2 x + 11 + 2

2 x - 7 = 2 - 3 x + 1

What is the answer to solvefor t,Y=2t^{1/2} ?
The answer to solvefor t,Y=2t^{1/2} is t=(Y^2)/4 {Y>= 0}