What is the answer to 3+sqrt(-x^2+4)=x^2+1 ?

The answer to 3+sqrt(-x^2+4)=x^2+1 is x=sqrt(3),x=-sqrt(3)

Solve for x: 3+sqrt(-x^2+4)=x^2+1

The solution is x=sqrt(3),x=-sqrt(3)

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3 + - x^{2} + 4 = x^{2} + 1

x = 3, x = - 3

Decimal Notation

x = 1.73205 \dots, x = - 1.73205 \dots

Solution steps

3 + - x^{2} + 4 = x^{2} + 1

Remove square roots

- x^{2} + 4 = x^{4} - 4 x^{2} + 4

Solve

- x^{2} + 4 = x^{4} - 4 x^{2} + 4 : x = 3, x = - 3, x = 0

x = 3, x = - 3, x = 0

Verify Solutions:

x = 3

True

, x = - 3

True

, x = 0

False

The solutions are

x = 3, x = - 3

t - 7 - 9 = 6

2 y - 1 - 1 = 2

y + 10 = 10

x^{\frac{5}{2}} = a

- x + 3.2 = 14.17

What is the answer to 3+sqrt(-x^2+4)=x^2+1 ?
The answer to 3+sqrt(-x^2+4)=x^2+1 is x=sqrt(3),x=-sqrt(3)
Solve for x: 3+sqrt(-x^2+4)=x^2+1
The solution is x=sqrt(3),x=-sqrt(3)