What is the answer to solvefor x,x^2=\sqrt[3]{32x} ?

The answer to solvefor x,x^2=\sqrt[3]{32x} is x=0,x=2

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solvefor x,x^2=\sqrt[3]{32x}

x = 0, x = 2

Solution steps

Take both sides of the equation to the power of

3 : x^{6} = 32 x

x^{6} = 32 x

Solve

x^{6} = 32 x : x = 0, x = 2

x = 0, x = 2

Verify Solutions:

x = 0

True

, x = 2

True

The solutions are

x = 0, x = 2

7 - 9 x = x + 7

(x - 4)^{\frac{7}{5}} = 128

x - x^{3} = 0

15 y + 9 - y + 16 = 7

t - 7 t + 18 = - 4

What is the answer to solvefor x,x^2=\sqrt[3]{32x} ?
The answer to solvefor x,x^2=\sqrt[3]{32x} is x=0,x=2