What is the answer to 5=sqrt((5-0)^2+(2-a)^2) ?

The answer to 5=sqrt((5-0)^2+(2-a)^2) is a=2

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5=sqrt((5-0)^2+(2-a)^2)

5 = (5 - 0)^{2} + (2 - a)^{2}

a = 2

Solution steps

5 = (5 - 0)^{2} + (2 - a)^{2}

Square both sides:

25 = a^{2} - 4 a + 29

25 = a^{2} - 4 a + 29

Solve

25 = a^{2} - 4 a + 29 : a = 2

a = 2

Verify Solutions:

a = 2

True

The solution is

a = 2

8 y^{0.8} y^{0.8} y = 8 y^{3}

4 a + 7 - 5 = 11

10 v - 24 = v

1.9 = 2 π \frac{L}{32}

5 = 5 x

What is the answer to 5=sqrt((5-0)^2+(2-a)^2) ?
The answer to 5=sqrt((5-0)^2+(2-a)^2) is a=2
Solve for a: 5=sqrt((5-0)^2+(2-a)^2)
The solution is a=2