What is the answer to solvefor a,sqrt(a)+b=11 ?

The answer to solvefor a,sqrt(a)+b=11 is a=121-22b+b^2 {b<= 11}

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solvefor a,sqrt(a)+b=11

solve for

a, a + b = 11

a = 121 - 22 b + b^{2} {b \leq 11}

Solution steps

a + b = 11

Move

b

to the right side

a = 11 - b

Square both sides:

a = 121 - 22 b + b^{2}

a = 121 - 22 b + b^{2}

Verify Solutions:

a = 121 - 22 b + b^{2} {b \leq 11}

The solution is

a = 121 - 22 b + b^{2} {b \leq 11}

3 x + 1 + 2 = x + 1

5 y - 1 = 7

1 = 0.0005777766 x + 1

10000 = 10000 x^{0.19} x n

- 5 x^{\frac{4}{3}} = - 1280

What is the answer to solvefor a,sqrt(a)+b=11 ?
The answer to solvefor a,sqrt(a)+b=11 is a=121-22b+b^2 {b<= 11}