What is the answer to solvefor x,y^2=-sqrt(x) ?

The answer to solvefor x,y^2=-sqrt(x) is x=y^4 {y=0}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,y^2=-sqrt(x)

solve for

x, y^{2} = - x

x = y^{4} {y = 0}

Solution steps

y^{2} = - x

Divide both sides by

- 1

\frac{y ^{2}}{- 1} = \frac{- x}{- 1}

Simplify

- y^{2} = x

Square both sides:

y^{4} = x

y^{4} = x

Switch sides

x = y^{4}

Verify Solutions:

x = y^{4} {y = 0}

The solution is

x = y^{4} {y = 0}

2 x + \frac{1}{2 x ^{2}} = 0

16 x + 1 = 17 x + 13

C = 3.2 x + 600

3 y + 1 = 4

What is the answer to solvefor x,y^2=-sqrt(x) ?
The answer to solvefor x,y^2=-sqrt(x) is x=y^4 {y=0}