What is the answer to (2x)/(sqrt(x^2+4))-1=0 ?

The answer to (2x)/(sqrt(x^2+4))-1=0 is x= 2/(sqrt(3))

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(2x)/(sqrt(x^2+4))-1=0

\frac{2 x}{x ^{2} + 4} - 1 = 0

x = \frac{2}{3}

Decimal Notation

x = 1.15470 \dots

Solution steps

\frac{2 x}{x ^{2} + 4} - 1 = 0

Multiply both sides by

x^{2} + 4

\frac{2 x}{x ^{2} + 4} x^{2} + 4 - 1 \cdot x^{2} + 4 = 0 \cdot x^{2} + 4

Simplify

2 x - x^{2} + 4 = 0

Remove square roots

x^{2} + 4 = 4 x^{2}

Solve

x^{2} + 4 = 4 x^{2} : x = \frac{2}{3}, x = - \frac{2}{3}

x = \frac{2}{3}, x = - \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

, x = - \frac{2}{3}

False

The solution is

x = \frac{2}{3}

\frac{2 x - 3}{x - 1} = 2

4 x + 1 = 40

4 1 + 16 x = 24

What is the answer to (2x)/(sqrt(x^2+4))-1=0 ?
The answer to (2x)/(sqrt(x^2+4))-1=0 is x= 2/(sqrt(3))
Solve for x: (2x)/(sqrt(x^2+4))-1=0
The solution is x= 2/(sqrt(3))