What is the answer to sqrt(3+2t)+sqrt(-1+4t)=1 ?

The answer to sqrt(3+2t)+sqrt(-1+4t)=1 is No Solution for t\in\mathbb{R}

Solve for t: sqrt(3+2t)+sqrt(-1+4t)=1

The solution is No Solution for t\in\mathbb{R}

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3 + 2 t + - 1 + 4 t = 1

No Solution for t \in R

Solution steps

3 + 2 t + - 1 + 4 t = 1

Remove square roots

9 - 12 t + 4 t^{2} = - 4 + 16 t

Solve

9 - 12 t + 4 t^{2} = - 4 + 16 t : t = \frac{13}{2}, t = \frac{1}{2}

t = \frac{13}{2}, t = \frac{1}{2}

Verify Solutions:

t = \frac{13}{2}

False

, t = \frac{1}{2}

False

The solution is

No Solution for t \in R

2 x - 3 - 4 = 0

5 x^{\frac{5}{2}} - 10 = 0

\frac{2}{3} w + 12 = 8 - 2 w

2 y + 6 + 7 = y + 6

2 n + 25 = - 5 - n

What is the answer to sqrt(3+2t)+sqrt(-1+4t)=1 ?
The answer to sqrt(3+2t)+sqrt(-1+4t)=1 is No Solution for t\in\mathbb{R}
Solve for t: sqrt(3+2t)+sqrt(-1+4t)=1
The solution is No Solution for t\in\mathbb{R}