What are the solutions to the equation 3x^2-18x+27=0 ?

The solutions to the equation 3x^2-18x+27=0 are x=3

Find the zeros of 3x^2-18x+27=0

The zeros of 3x^2-18x+27=0 are x=3

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3 x^{2} - 18 x + 27 = 0

x = 3

Solution steps

3 x^{2} - 18 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 27}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 27 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 3}

x = \frac{- ( - 18 )}{2 \cdot 3}

\frac{- ( - 18 )}{2 \cdot 3} = 3

x = 3

The solution to the quadratic equation is:

x = 3

15 r - 15 < 15 r + 5

x^{2} = 12

- 2 (- 3)

4 - (- h) = 68

1.18 \cdot 1 0^{- 5} = 27.84 (0.1)^{0.0497}

What are the solutions to the equation 3x^2-18x+27=0 ?
The solutions to the equation 3x^2-18x+27=0 are x=3
Find the zeros of 3x^2-18x+27=0
The zeros of 3x^2-18x+27=0 are x=3