What is the answer to solvefor y,x=sqrt(4-y)+1 ?

The answer to solvefor y,x=sqrt(4-y)+1 is y=-x^2+2x+3 {x>= 1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor y,x=sqrt(4-y)+1

solve for

y, x = 4 - y + 1

y = - x^{2} + 2 x + 3 {x \geq 1}

Solution steps

x = 4 - y + 1

Switch sides

4 - y + 1 = x

Move

1

to the right side

4 - y = x - 1

Square both sides:

4 - y = x^{2} - 2 x + 1

4 - y = x^{2} - 2 x + 1

Solve

4 - y = x^{2} - 2 x + 1 : y = - x^{2} + 2 x + 3

y = - x^{2} + 2 x + 3

Verify Solutions:

y = - x^{2} + 2 x + 3 {x \geq 1}

The solution is

y = - x^{2} + 2 x + 3 {x \geq 1}

p^{- \frac{3}{4}} = 8

9 x^{\frac{7}{2}} - 63 = 0

\frac{6 ( x + 4 ) - 4}{2} = 4

x, x^{0.7} = 2

3 = 16 m - 5

What is the answer to solvefor y,x=sqrt(4-y)+1 ?
The answer to solvefor y,x=sqrt(4-y)+1 is y=-x^2+2x+3 {x>= 1}