What is the answer to solvefor x,2f=sqrt(4x+21) ?

The answer to solvefor x,2f=sqrt(4x+21) is x=(4f^2-21)/4 {f>= 0}

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solvefor x,2f=sqrt(4x+21)

solve for

x, 2 f = 4 x + 21

x = \frac{4 f ^{2} - 21}{4} {f \geq 0}

Solution steps

2 f = 4 x + 21

Square both sides:

4 f^{2} = 4 x + 21

4 f^{2} = 4 x + 21

Solve

4 f^{2} = 4 x + 21 : x = \frac{4 f ^{2} - 21}{4}

x = \frac{4 f ^{2} - 21}{4}

Verify Solutions:

x = \frac{4 f ^{2} - 21}{4} {f \geq 0}

The solution is

x = \frac{4 f ^{2} - 21}{4} {f \geq 0}

186 = 16 8^{2} + x^{2}

b - 5 = 20

x + 1 = 3 x + 2

3 (x - 5)^{\frac{3}{2}} - 6 = 18

y^{\frac{1}{3}} = y - 10

What is the answer to solvefor x,2f=sqrt(4x+21) ?
The answer to solvefor x,2f=sqrt(4x+21) is x=(4f^2-21)/4 {f>= 0}