What is the answer to sqrt(3x^2-4x+1)=x+1 ?

The answer to sqrt(3x^2-4x+1)=x+1 is x=3,x=0

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sqrt(3x^2-4x+1)=x+1

3 x^{2} - 4 x + 1 = x + 1

x = 3, x = 0

Solution steps

3 x^{2} - 4 x + 1 = x + 1

Square both sides:

3 x^{2} - 4 x + 1 = x^{2} + 2 x + 1

3 x^{2} - 4 x + 1 = x^{2} + 2 x + 1

Solve

3 x^{2} - 4 x + 1 = x^{2} + 2 x + 1 : x = 3, x = 0

x = 3, x = 0

Verify Solutions:

x = 3

True

, x = 0

True

The solutions are

x = 3, x = 0

\frac{5 x - 3}{2 x - 1} = 5

627 = 5 k^{\frac{4}{3}} + 2

5 = 4 x - 2

0 = \frac{x + 2}{x - 10}

x, z = x - y

What is the answer to sqrt(3x^2-4x+1)=x+1 ?
The answer to sqrt(3x^2-4x+1)=x+1 is x=3,x=0
Solve for x: sqrt(3x^2-4x+1)=x+1
The solution is x=3,x=0