What is the answer to \sqrt[5]{16+4\sqrt[3]{x-1}}=2 ?

The answer to \sqrt[5]{16+4\sqrt[3]{x-1}}=2 is x=65

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\sqrt[5]{16+4\sqrt[3]{x-1}}=2

x = 65

Solution steps

Take both sides of the equation to the power of

Move

16

to the right side

Divide both sides by

4

Take both sides of the equation to the power of

3 : x - 1 = 64

x - 1 = 64

Solve

x - 1 = 64 : x = 65

x = 65

Verify Solutions:

x = 65

True

The solution is

x = 65

264 - x^{2} - 14 = - 6

x - 16 x - 512 = 0

v^{\frac{5}{4}} = 243

8 + 3 x - x = 0

What is the answer to \sqrt[5]{16+4\sqrt[3]{x-1}}=2 ?
The answer to \sqrt[5]{16+4\sqrt[3]{x-1}}=2 is x=65
Solve for x: \sqrt[5]{16+4\sqrt[3]{x-1}}=2
The solution is x=65