What is the answer to 7^2=sqrt(b^2+b^2) ?

The answer to 7^2=sqrt(b^2+b^2) is b=(49)/(sqrt(2)),b=-(49)/(sqrt(2))

Solve for b: 7^2=sqrt(b^2+b^2)

The solution is b=(49)/(sqrt(2)),b=-(49)/(sqrt(2))

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7^{2} = b^{2} + b^{2}

b = \frac{49}{2}, b = - \frac{49}{2}

Decimal Notation

b = 34.64823 \dots, b = - 34.64823 \dots

Solution steps

7^{2} = b^{2} + b^{2}

Square both sides:

2401 = 2 b^{2}

2401 = 2 b^{2}

Solve

2401 = 2 b^{2} : b = \frac{49}{2}, b = - \frac{49}{2}

b = \frac{49}{2}, b = - \frac{49}{2}

Verify Solutions:

b = \frac{49}{2}

True

, b = - \frac{49}{2}

True

The solutions are

b = \frac{49}{2}, b = - \frac{49}{2}

x^{- \frac{5}{9}} = 3

x, x^{2} + 18 - 3 = 0

2 x + 3 = x - 6

u^{\frac{1}{3}} = 4

2 x + 3 = x + 2

What is the answer to 7^2=sqrt(b^2+b^2) ?
The answer to 7^2=sqrt(b^2+b^2) is b=(49)/(sqrt(2)),b=-(49)/(sqrt(2))
Solve for b: 7^2=sqrt(b^2+b^2)
The solution is b=(49)/(sqrt(2)),b=-(49)/(sqrt(2))